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WebSolution. Let AP and BP be the two tangents to the circle with centre O. To Prove : AP = BP. Proof : In Δ AOP and Δ BOP. OA = OB (radii of the same circle) ∠OAP =∠OBP = 90∘ (since tangent at any point of a circle is perpendicular to the radius through the point of contact) OP = OP (common) ∴ ΔAOP ≅ΔBOP (by R.H.S. congruence criterion) WebTelegram: Contact @mathsbyarunsirchannel. Maths By Arun Sir Official. 83 828 subscribers. Quantitative Aptitude Top Educator. "7+ yr of teaching experience. Qualified … Web5 gen 2024 · Science Target 70+ Part 1 SSLC EXAM 2024. ARUN MATHS HUB. 53.4K subscribers. Join. Subscribe. Like. Share. 3.6K views 4 days ago. 🔹Join The Telegram group … ctrl reviews